Convert Data to Binary

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• 6 Comments
• • 

  • You can't. binary is a number system, any integer can be rendered as binary, but it can't be *converted* to binary, that makes no sense

    Perhaps you need to explain what you want to do here ?

    #1; Sun, 09 Sep 2007 02:12:00 GMT
• • 
  • Thanks. I want to convert a string or a interger into a binary number to do bit operate
    #2; Sun, 09 Sep 2007 02:13:00 GMT
• • 
  • You can use Convert.ToInt32 to convert a string to int (put the conversion in a try block if you think it's error prone) and then use bitwise operators on the int.
    #3; Sun, 09 Sep 2007 02:14:00 GMT
• • 
  • Also have a look at the new Int32.TryParse method if you want parse strings without needing to catch an exception for invalid input.
    #4; Sun, 09 Sep 2007 02:15:00 GMT
• • 

  • An integer if also a binary/hex number, the only difference is the way that it is printed on the screen.

    Sub Main()

    Dim n As Integer

    n = 0

    n = n Or 1

    n = n Or 8

    Console.WriteLine(ConvertToBinary(n))

    n = n Xor 32

    Console.WriteLine(ConvertToBinary(n))

    n = n And 32

    Console.WriteLine(ConvertToBinary(n))

    n = Not n

    Console.WriteLine(ConvertToBinary(n))

    Console.ReadLine()

    End Sub

    Public Function ConvertToBinary(ByVal num As Integer) As String

    Dim p, b As Integer

    Dim result As String

    b = 1

    result = ""

    For p = 0 To 8

    If (num And b) Then

    result = "1" & result

    Else

    result = "0" & result

    End If

    b *= 2

    Next

    Return result

    End Function

    The function ConvertToBinary only put each bit in the number into a readable string for the user to see and all binary operation are executed directly on the integer.

    #5; Sun, 09 Sep 2007 02:16:00 GMT
• • 
  • You can do the converToBinary thing with:

    Convert.ToString(someint, 2)

    If you have some bits set in a value and you need to read/set/unset the bits then just use logic. You could use the bitarray class I suppose...

     Dim someint As Integer = 509385034 
     Dim someintBinaryRepresentation As String = Convert.ToString(someint, 2) 
     Debug.WriteLine(someintBinaryRepresentation) 
     ' which is : 
     ' 00011110 01011100 10011001 01001010 say we wat to change these bits: 
     ' 1 0 1 1 
     ' then we can use the bitarray class 
     ' there are several overloads of the constructor. We have to pass it an int array 
     Dim someintAsArray() As Integer = {someint} 
     Dim ba As New BitArray(someintAsArray) 
     ' so set bis 0, 2, 16 to 1, and bit 12 to 0 
     ba(0) = True 
     ba(2) = True 
     ba(16) = True 
     ba(12) = False 
     ' and see what we got: 
     ba.CopyTo(someintAsArray, 0) 
     Debug.WriteLine(Convert.ToString(someintAsArray(0), 2)) 
     ' before: 00011110 01011100 10011001 01001010 
     ' after: 00011110 01011101 10001001 01001111 
     ' Or you can just use logic 
     someint = 509385034 ' reset it 
     ' set bit at 0 
     someint = someint Or (2 ^ 0) 
     ' set bit at 2 
     someint = someint Or (2 ^ 2) 
     ' set bit at 16 
     someint = someint Or (2 ^ 16) 
     ' unset bit at 12 
     someint = someint And (Not (2 ^ 12)) 
     
     Debug.WriteLine(Convert.ToString(someint, 2)) ' same as above 

    #6; Sun, 09 Sep 2007 02:17:00 GMT